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Proof step 4 from proof fill-append-shift (previous step)

n = n0 + # ar0, # ar0 ≤ n ⊦ fill(ar0 + ar1, a, n, m) = ar0 + fill(ar1, a, n0, m)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
⊦ fill(ar0 + ar1, a, n0 + # ar0, m) = ar0 + fill(ar1, a, n0, m)

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m ≤ m + n; (s)