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Proof step 6 from proof range-copy-drop (previous step)

range=(ar2, n2, copy(ar, n, ar0, n0, m0), n1, m1), n + m0 ≤ # ar, n0 + m0 ≤ # ar0, n0 + m0 ≤ n1 ∨ n1 + m1 ≤ n0 ⊦ n2 + m1 ≤ # ar2 ∧ n1 + m1 ≤ # ar0 ∧ (n3 < m1 → ar2[n2 + n3] = ar0[n1 + n3])

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ range=(ar0, n0, ar1, n1, m) ↔ n0 + m ≤ # ar0 ∧ n1 + m ≤ # ar1 ∧ (∀ n. n < m → ar0[n0 + n] = ar1[n1 + n])
Proof step 8:
n0 + m0 ≤ # ar0, n + m0 ≤ # ar, n2 + m1 ≤ # ar2, n1 + m1 ≤ # copy(ar, n, ar0, n0, m0), ∀ n3. n3 < m1 → ar2[n2 + n3] = copy(ar, n, ar0, n0, m0)[n1 + n3], n0 + m0 ≤ n1 ∨ n1 + m1 ≤ n0 ⊦ n2 + m1 ≤ # ar2 ∧ n1 + m1 ≤ # ar0 ∧ (n3 < m1 → ar2[n2 + n3] = ar0[n1 + n3])

Rule argument

spec: <toplevel> name: range-eq-ext seq: ⊦ range=(ar0, n0, ar1, n1, m) ↔ n0 + m ≤ # ar0 ∧ n1 + m ≤ # ar1 ∧ (∀ n. n < m → ar0[n0 + n] = ar1[n1 + n]) subst: [m, n1, ar1, n0, ar0] → [m1, n1, copy(ar, n, ar0, n0, m0), n2, ar2] flags: <all paths>

Additional information

Used terms: m1, n1, copy(ar, n, ar0, n0, m0), n2, ar2