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Proof step 10 from proof range-copy-inner (previous step)

range=(ar2, n2, copy(ar, n, ar0, n3 + n1, m0), n1, n0 + n3 + m0), n + m0 ≤ # ar, (n3 + n1) + m0 ≤ # ar0 ⊦ range=(ar2, n2, ar0, n1, n3) ∧ range=(ar2, n3 + n2, ar, n, m0) ∧ range=(ar2, n3 + n2 + m0, ar0, (n3 + n1) + m0, n0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 11:
⊦ range=(ar0, n0, ar1, n1, m) ↔ n0 + m ≤ # ar0 ∧ n1 + m ≤ # ar1 ∧ (∀ n. n < m → ar0[n0 + n] = ar1[n1 + n])
Proof step 12:
(n3 + n1) + m0 ≤ # ar0, n + m0 ≤ # ar, n2 + n0 + n3 + m0 ≤ # ar2, n1 + n0 + n3 + m0 ≤ # copy(ar, n, ar0, n3 + n1, m0), ∀ n4. n4 < n0 + n3 + m0 → ar2[n2 + n4] = copy(ar, n, ar0, n3 + n1, m0)[n1 + n4] ⊦ range=(ar2, n2, ar0, n1, n3) ∧ range=(ar2, n3 + n2, ar, n, m0) ∧ range=(ar2, n3 + n2 + m0, ar0, (n3 + n1) + m0, n0)

Rule argument

spec: <toplevel> name: range-eq-ext seq: ⊦ range=(ar0, n0, ar1, n1, m) ↔ n0 + m ≤ # ar0 ∧ n1 + m ≤ # ar1 ∧ (∀ n. n < m → ar0[n0 + n] = ar1[n1 + n]) subst: [m, n1, ar1, n0, ar0] → [n0 + n3 + m0, n1, copy(ar, n, ar0, n3 + n1, m0), n2, ar2] flags: <all paths>

Additional information

Used terms: n0 + n3 + m0, n1, copy(ar, n, ar0, n3 + n1, m0), n2, ar2