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Proof step 7 from proof range-copy-lower (previous step)

n + n1 + n3 ≤ # ar, n0 + n1 + n3 ≤ # ar0, n3 + n0 ≤ # ar0, n0 ≤ # ar0, n1 ≤ m1 ⊦ range=(ar2, n2, copy(ar, n, ar0, n0, n1 + n3), n3 + n0, m1) ↔ range=(ar2, n2, ar, n + n3, n1) ∧ range=(ar2, n1 + n2, ar0, n0 + n1 + n3, m1 - n1)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 8:
m1 = n4 + n1, n1 ≤ m1, n0 ≤ # ar0, n3 + n0 ≤ # ar0, n0 + n1 + n3 ≤ # ar0, n + n1 + n3 ≤ # ar ⊦ range=(ar2, n2, copy(ar, n, ar0, n0, n1 + n3), n3 + n0, m1) ↔ range=(ar2, n2, ar, n + n3, n1) ∧ range=(ar2, n1 + n2, ar0, n0 + n1 + n3, n4)

Rule argument

spec: nat name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [m1, n1, n4]

Additional information

Used simplifier rules: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: m1, n1, n4