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Proof step 18 from proof range-copy-outer (previous step)

range=(ar2, n2, ar, n + n3, m1), n + m0 ≤ # ar, n0 + m0 ≤ # ar0, (n3 + n0) + m1 ≤ # ar0, n3 + m1 ≤ m0 ⊦ n2 + m1 ≤ # ar2 ∧ (n3 + n0) + m1 ≤ # copy(ar, n, ar0, n0, m0) ∧ (∀ n4. n4 < m1 → ar2[n2 + n4] = copy(ar, n, ar0, n0, m0)[(n3 + n0) + n4])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
range=(ar2, n2, ar, n + n3, m1), n3 + m1 ≤ m0, (n3 + n0) + m1 ≤ # ar0, n0 + m0 ≤ # ar0, n + m0 ≤ # ar ⊦ n2 + m1 ≤ # ar2 ∧ (n1 < m1 → ar2[n2 + n1] = copy(ar, n, ar0, n0, m0)[(n3 + n0) + n1])

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ # copy(ar, m, ar0, m0, n) = # ar0; (s)