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Proof step 2 from proof range-copy-outer (previous step)

n0 + m0 ≤ # ar0, n + m0 ≤ # ar, n1 + m1 ≤ n0 + m0, n0 ≤ n1 ⊦ range=(ar2, n2, copy(ar, n, ar0, n0, m0), n1, m1) ↔ range=(ar2, n2, ar, n + (n1 - n0), m1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
n0 ≤ n1, n1 + m1 ≤ n0 + m0, n + m0 ≤ # ar, n0 + m0 ≤ # ar0, n1 + m1 ≤ # ar0 ⊦ range=(ar2, n2, copy(ar, n, ar0, n0, m0), n1, m1) ↔ range=(ar2, n2, ar, n + (n1 - n0), m1)

Rule argument

Additional information

Used simplifier rules: let: ⊦ n ≤ n0 ∧ n0 ≤ n1 → n ≤ n1; (forward) from specification nat