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Proof step 5 from proof range-copy-outer (previous step)

n + m0 ≤ # ar, n0 + m0 ≤ # ar0, (n3 + n0) + m1 ≤ # ar0, n3 + m1 ≤ m0 ⊦ range=(ar2, n2, copy(ar, n, ar0, n0, m0), n3 + n0, m1) ↔ range=(ar2, n2, ar, n + n3, m1)

User applied rule case distinction

And obtained the following new goals

Proof step 6:
range=(ar2, n2, copy(ar, n, ar0, n0, m0), n3 + n0, m1), n3 + m1 ≤ m0, (n3 + n0) + m1 ≤ # ar0, n0 + m0 ≤ # ar0, n + m0 ≤ # ar ⊦ range=(ar2, n2, ar, n + n3, m1)
Proof step 16:
range=(ar2, n2, ar, n + n3, m1), n3 + m1 ≤ m0, (n3 + n0) + m1 ≤ # ar0, n0 + m0 ≤ # ar0, n + m0 ≤ # ar ⊦ range=(ar2, n2, copy(ar, n, ar0, n0, m0), n3 + n0, m1)

Rule argument

pos: right 1

Proof step 5 from proof range-copy-outer (previous step)

User applied rule case distinction

And obtained the following new goals

Rule argument

Additional information