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Proof step 2 from proof range-eq-append-shift (previous step)

n ≥ # ar0 ⊦ range=(ar0 + ar1, n, ar2, m0, m1) ↔ range=(ar1, n - # ar0, ar2, m0, m1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
# ar0 ≤ n ⊦ range=(ar0 + ar1, n, ar2, m0, m1) ↔ range=(ar1, n - # ar0, ar2, m0, m1)

Rule argument

Additional information

Used simplifier rules: ⊦ n ≥ m ↔ m ≤ n; (s)