| n < n2 ⊦ range=(ar0, n0, ar1, n1, n2) ↔ ar0[n0 + n] = ar1[n1 + n] ∧ range=(ar0, n0, ar1, n1, n2) |
n < n2, range=(ar0, n0, ar1, n1, n2) ⊦ ar0[n0 + n] = ar1[n1 + n]
Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic