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Proof step 10 from proof range-eq-resize (previous step)

n1 + m ≤ # ar1, n1 + m ≤ n, n ≤ # ar1, n0 + m ≤ # ar0, ∀ n2. n2 < m → ar0[n0 + n2] = resize(ar1, n)[n1 + n2] ⊦ n0 + m ≤ # ar0 ∧ n1 + m ≤ # ar1 ∧ (∀ n. n < m → ar0[n0 + n] = ar1[n1 + n])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
n2 < m, n1 + m ≤ # ar1, n1 + m ≤ n, n ≤ # ar1, n0 + m ≤ # ar0, ∀ n2. n2 < m → ar0[n0 + n2] = resize(ar1, n)[n1 + n2] ⊦ ar0[n0 + n2] = ar1[n1 + n2]

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic