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Proof step 3 from proof range-eq-resize (previous step)

n ≤ # ar1 ⊦ range=(ar0, n0, resize(ar1, n), n1, m) ↔ range=(ar0, n0, ar1, n1, m) ∧ m + n1 ≤ n

User applied rule case distinction

And obtained the following new goals

Proof step 4:
range=(ar0, n0, resize(ar1, n), n1, m), n ≤ # ar1 ⊦ range=(ar0, n0, ar1, n1, m) ∧ m + n1 ≤ n
Proof step 15:
range=(ar0, n0, ar1, n1, m), n ≤ # ar1, m + n1 ≤ n ⊦ range=(ar0, n0, resize(ar1, n), n1, m)

Rule argument

pos: right 1

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