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Proof step 1 from proof range-eq-splice-less (conclusion)

⊦ m1 ≤ m0 ∧ n + m0 ≤ # ar ∧ # ar0 < n0 + m1 ∧ m1 ≠ 0 ∧ n1 ≤ n0 → (range=(ar2, n2, splice(ar, n, ar0, n0, m0), n1, m1) ↔ range=(ar2, n2, splice(ar, n, ar0, n0, m1), n1, m1))

System applied rule normalize

And obtained the following new goals

Proof step 2:
# ar0 < n0 + m1, m1 ≤ m0, n + m0 ≤ # ar, n1 ≤ n0 ⊦ range=(ar2, n2, splice(ar, n, ar0, n0, m0), n1, m1) ↔ range=(ar2, n2, splice(ar, n, ar0, n0, m1), n1, m1), m1 = 0

Proof step 1 from proof range-eq-splice-less (conclusion)

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information