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Proof step 15 from proof range-eq-splice-less (previous step)

n3 < m0, n3 < m1, # ar0 < n0 + m1, m1 ≤ m0, n + m0 ≤ # ar, n1 ≤ n0, n2 + m1 ≤ # ar2, n1 + m1 ≤ max(# ar0, n0 + m0), ∀ n3. n3 < m1 → ar2[n2 + n3] = splice(ar, n, ar0, n0, m0)[n1 + n3] ⊦ ar2[n2 + n3] = copy(ar, n, resize(ar0, n0 + m1), n0, m1)[n1 + n3], m0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
# ar0 < n0 + m1, n3 < m1, n3 < m0, n1 + m1 ≤ max(# ar0, n0 + m0), n2 + m1 ≤ # ar2, n1 ≤ n0, n + m0 ≤ # ar, m1 ≤ m0, ∀ n3. n3 < m1 → ar2[n2 + n3] = splice(ar, n, ar0, n0, m0)[n1 + n3] ⊦ ar2[n2 + n3] = copy(ar, n, resize(ar0, n0 + m1), n0, m1)[n1 + n3]

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)