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Proof step 1 from proof range-eq-subarrays (conclusion)

⊦ range=(ar0, n0, ar1, n1, m) ↔ n0 + m ≤ # ar0 ∧ n1 + m ≤ # ar1 ∧ subarray(ar0, n0, m) = subarray(ar1, n1, m)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information