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Proof step 8 from proof range-eq-trans (previous step)

range=(ar0, n0, ar1, n1, m), n1 + m ≤ # ar1, n2 + m ≤ # ar2, ∀ n. n < m → ar1[n1 + n] = ar2[n2 + n] ⊦ n0 + m ≤ # ar0 ∧ n2 + m ≤ # ar2 ∧ (n < m → ar0[n0 + n] = ar2[n2 + n])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
range=(ar0, n0, ar1, n1, m), n2 + m ≤ # ar2, n1 + m ≤ # ar1, ∀ n. n < m → ar1[n1 + n] = ar2[n2 + n] ⊦ n0 + m ≤ # ar0 ∧ (n < m → ar0[n0 + n] = ar2[n2 + n])

Proof step 8 from proof range-eq-trans (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information