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Proof step 29 from proof range-extend (previous step)

range=(ar0, n0, ar1, n1, m0), range=(ar, n, ar1, n1 + m0, m1), n + m1 ≤ # ar, n0 + m0 + m1 ≤ # ar0 ⊦ n0 + m0 + m1 ≤ # copy(ar, n, ar0, n0 + m0, m1) ∧ n1 + m0 + m1 ≤ # ar1 ∧ (∀ n2. n2 < m0 + m1 → copy(ar, n, ar0, n0 + m0, m1)[n0 + n2] = ar1[n1 + n2])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 30:
range=(ar, n, ar1, n1 + m0, m1), range=(ar0, n0, ar1, n1, m0), n0 + m0 + m1 ≤ # ar0, n + m1 ≤ # ar ⊦ n1 + m0 + m1 ≤ # ar1 ∧ (n2 < m0 + m1 → copy(ar, n, ar0, n0 + m0, m1)[n0 + n2] = ar1[n1 + n2])

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ # copy(ar, m, ar0, m0, n) = # ar0; (s)