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Proof step 23 from proof splice-resize-less (previous step)

n < n1 ⊦ splice(ar0, n0, ar1, n1, m0)[n] = (# ar1 ≤ n ⊃ zero;ar1[n]), m0 = 0, max(# ar1, n1 + m0) ≤ n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 24:
n < max(# ar1, n1 + m0), n < n1 ⊦ splice(ar0, n0, ar1, n1, m0)[n] = (# ar1 ≤ n ⊃ zero;ar1[n]), m0 = 0

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m ≤ n ↔ ¬ n < m; (ss)