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Proof step 3 from proof splice-resize-less (previous step)

n1 ≤ m1 ⊦ m0 = 0, resize(splice(ar0, n0, ar1, n1, m0), m1) = resize(splice(ar0, n0, ar1, n1, min(m0, m1 - n1)), m1)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 4:
m1 = n2 + n1, n1 ≤ m1 ⊦ m0 = 0, resize(splice(ar0, n0, ar1, n1, m0), m1) = resize(splice(ar0, n0, ar1, n1, min(m0, n2)), m1)

Rule argument

spec: nat name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [m1, n1, n]

Additional information

Used simplifier rules: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: m1, n1, n