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Proof step 48 from proof splice-resize-less (previous step)

n < # ar1, n < n2 + n1, n1 + n2 ≤ # ar1, n2 ≤ m0, n1 + m0 ≤ # ar1 ⊦ copy(ar0, n0, ar1, n1, m0)[n] = (n < n1 ⊃ ar1[n];ar0[n + n0 - n1]), m0 = 0, n2 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 49:
n < n2 + n1, n < # ar1, n1 + m0 ≤ # ar1, n2 ≤ m0, n1 + n2 ≤ # ar1 ⊦ (n < n1 ∨ n1 + m0 ≤ n ⊃ ar1[n];ar0[n + n0 - n1]) = (n < n1 ⊃ ar1[n];ar0[n + n0 - n1]), m0 = 0, n2 = 0

Rule argument

Additional information

Used simplifier rules: ⊦ m0 < # ar1 → copy(ar0, n, ar1, n0, m)[m0] = (m0 < n0 ∨ n0 + m ≤ m0 ⊃ ar1[m0];ar0[m0 + n - n0]); (s)