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Proof step 60 from proof splice-resize-less (previous step)

n = n3 + n1, n < n1 + n2, max(# ar1, n1 + m0) < n2 + n1, n < n2 + n1, # ar1 < n1 + n2, n2 ≤ m0, max(# ar1, n1 + m0) ≤ n, n1 ≤ n ⊦ m0 = 0, n2 = 0, zero = ar0[n3 + n0]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 61:
# ar1 < n1 + n2, max(# ar1, n1 + m0) < n2 + n1, n3 < n2, n3 < m0, max(# ar1, n1 + m0) ≤ n3 + n1, n2 ≤ m0 ⊦ zero = ar0[n3 + n0]

Rule argument

Additional information

Used simplifier rules: fle: ⊦ m < n ∧ n ≤ n0 → m < n0; (forward) from specification nat%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m < n → n ≠ 0; (s)% ⊦ m + n < m + n0 ↔ n < n0; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m ≤ m + n; (s)