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Proof step 2 from proof subarray-append-elim-left (
previous step
)
n0 + m ≤ # ar0 + # ar1, # ar0 ≤ n0 ⊦ subarray(ar0 + ar1, n0, m) = subarray(ar1, n0 - # ar0, m)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 3
:
# ar0 ≤ n0, n0 + m ≤ # ar0 + # ar1 ⊦ subarray(ar0 + ar1, n0, m) = subarray(ar1, n0 - # ar0, m)
Rule argument
Additional information