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Proof step 4 from proof subarray-append-shift-left (previous step)

# ar0 = n0 + n, n + m = # ar0 + # ar1, n ≤ # ar0 ⊦ subarray(ar0 + ar1, n, m) = subarray(ar0, n, n0) + ar1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
# ar0 = n0 + n ⊦ subarray(ar0 + ar1, n, n0 + # ar1) = subarray(ar0, n, n0) + ar1

Rule argument

Additional information

Used simplifier rules: ⊦ m ≤ m + n; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m + n = m + n0 ↔ n = n0; (s)