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Proof step 15 from proof subarray-eq-elim (previous step)

⊦ ∃ ar0, ar2. ar = ar0 + ar2 ∧ # ar2 = 0

User applied rule exists right

And obtained the following new goals

Rule argument

pos: right 1 terms: ar, mkarray(0) abort: F discard: T computed: F

Additional information

Used simplifier rules: append-zero-right: ⊦ ar + mkarray(0) = ar;%append-a: ⊦ (ar + ar0) + ar1 = ar + ar0 + ar1;% ⊦ # mkarray(n) = n; (s) Used terms: ar, mkarray(0)