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Proof step 52 from proof subarray-eq-elim (previous step)

# ar = (n1 + m) + n ⊦ ar = subarray(ar, 0, n) + subarray(ar, # subarray(ar, 0, n), m) + subarray(ar, n + m, n1) ∧ # subarray(ar, 0, n) = n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 53:
⊦ (ar + ar0) + ar1 = ar + ar0 + ar1
Proof step 54:
# ar = (n1 + m) + n ⊦ ar = subarray(ar, 0, n) + subarray(ar, n, m) + subarray(ar, n + m, n1)

Rule argument

Additional information

Used simplifier rules: append-a: ⊦ (ar + ar0) + ar1 = ar + ar0 + ar1;% ⊦ # subarray(ar, m, n) = n; (s)