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Proof step 65 from proof subarray-eq-elim (previous step)

⊦ subarray(ar2 + ar1, # ar2, # ar1) = ar1

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: subarray-append-elim-left0 seq: ⊦ n = # ar0 ∧ m ≤ # ar1 → subarray(ar0 + ar1, n, m) = subarray(ar1, 0, m) subst: [m, n, ar1, ar0] → [# ar1, # ar2, ar1, ar2] flags: <all paths>

Additional information

Used simplifier rules: # ar = n ⊦ subarray(ar, 0, n) = ar; (s)% ⊦ m ≤ m; (s) Used terms: # ar1, # ar2, ar1, ar2