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Proof step 17 from proof subarray-split-at (previous step)

# ar = n0 + n, n1 < n0 + n, n1 < # subarray(ar, 0, n) + # subarray(ar, n, n0), n ≤ n1, # subarray(ar, 0, n) ≤ n1 ⊦ ar[n1] = subarray(ar, n, n0)[n1 - # subarray(ar, 0, n)], n0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
# ar = n0 + n, n1 < n0 + n, n1 < n + n0, n ≤ n1 ⊦ ar[n1] = subarray(ar, n, n0)[n1 - n], n0 = 0

Rule argument

Additional information

Used simplifier rules: ⊦ # subarray(ar, m, n) = n; (s)