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Proof step 12 from proof subarray-split-first (previous step)

n0 + m < # ar, n < m + 1, n ≤ m ⊦ ar[n0 + n] = (mkarray(1)[0, ar[n0]] + subarray(ar, n0 + 1, m))[n]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
n0 + m < # ar, n ≤ m ⊦ ar[n0 + n] = (mkarray(1)[0, ar[n0]] + subarray(ar, n0 + 1, m))[n]

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m ≤ n → (n < m ↔ false); (s)% ⊦ m < n + 1 ↔ ¬ n < m; (s)