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Proof step 3 from proof subarray-split-first (previous step)

n0 + n1 ≤ # ar ⊦ n1 = 0, subarray(ar, n0, n1) = mkarray(1)[0, ar[n0]] + subarray(ar, n0 + 1, n1 - 1)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 4:
n1 = m + 1, n0 + n1 ≤ # ar ⊦ n1 = 0, subarray(ar, n0, n1) = mkarray(1)[0, ar[n0]] + subarray(ar, n0 + 1, m)

Rule argument

spec: nat name: elim-pred-c seq: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1 subst: [n, m] → [n1, m]

Additional information

Used simplifier rules: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1; (elim) Used terms: n1, m