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Proof step 1 from proof subarray-split-size (conclusion)

⊦ subarray(ar, n, n0 + n1) = subarray(ar, n, n0) + subarray(ar, n + n0, n1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ subarray(ar, m, n) = copy(ar, m, mkarray(n), 0, n)
Proof step 3:
⊦ copy(ar, n, mkarray(n0 + n1), 0, n0 + n1) = subarray(ar, n, n0) + subarray(ar, n + n0, n1)

Rule argument

spec: array-copy name: Subarray seq: ⊦ subarray(ar, m, n) = copy(ar, m, mkarray(n), 0, n) subst: [n, m, ar] → [n0 + n1, n, ar] flags: <all paths>

Additional information

Used terms: n0 + n1, n, ar