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Proof step 22 from proof subarray-split-size (previous step)

n2 = n3 + n0, n2 < n0 + n1, n0 ≤ n2 ⊦ ar[n2 + n] = copy(ar, n + n0, mkarray(n1), 0, n1)[n3], n1 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
n3 < n1 ⊦ ar[(n3 + n0) + n] = copy(ar, n + n0, mkarray(n1), 0, n1)[n3]

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m < n → n ≠ 0; (s)% ⊦ m + n < m + n0 ↔ n < n0; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m ≤ m + n; (s)