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Proof step 13 from proof emptystream-cancel (previous step)

# σ = ⌜n⌝ , ∀ n0. ⌜n0⌝ < ⌜n⌝ + # σ⊥ → (σ + σ⊥)[n0] = zero, # σ⊥ = ∞ ∨ σ = [] ⊦ ⌜n⌝ = #(σ⊥ to n) ∧ (n0 < n → σ[n0] = (σ⊥ to n)[n0])

User applied rule all left

And obtained the following new goals

Proof step 14:
# σ = ⌜n⌝ , ⌜n⌝ < ⌜n⌝ + # σ⊥ → (σ + σ⊥)[n] = zero, ∀ n0. ⌜n0⌝ < ⌜n⌝ + # σ⊥ → (σ + σ⊥)[n0] = zero, # σ⊥ = ∞ ∨ σ = [] ⊦ ⌜n⌝ = #(σ⊥ to n) ∧ (n0 < n → σ[n0] = (σ⊥ to n)[n0])

Rule argument

pos: left 2 terms: n abort: F discard: F computed: F

Additional information

Used terms: n