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Proof step 21 from proof emptystream-cancel (previous step)

# σ = ⌜n⌝ , n0 < n, ∀ n1. (σ + ⌜λ n. zero⌝ )[n1] = zero ⊦ σ[n0] = zero

User applied rule all left

And obtained the following new goals

Proof step 22:
# σ = ⌜n⌝ , (σ + ⌜λ n. zero⌝ )[n0] = zero, n0 < n ⊦ σ[n0] = zero

Rule argument

pos: left 3 terms: n0 abort: F discard: T computed: F

Additional information

Used terms: n0