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Proof step 24 from proof emptystream-cancel (previous step)

# σ = ⌜n⌝ , σ = σ⊥ to n ⊦ σ + σ⊥ = σ⊥

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 25:
#(σ⊥ to n) = ⌜n⌝ ⊦ (σ⊥ to n) + σ⊥ = σ⊥

Rule argument

Additional information