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Proof step 4 from proof emptystream-cancel (
previous step
)
# σ = ⌜n⌝ ⊦ # σ = ∞, σ + σ⊥ = σ⊥ ↔ σ = σ⊥ to n
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 5
:
# σ = ⌜n⌝ ⊦ σ + σ⊥ = σ⊥ ↔ σ = σ⊥ to n
Rule argument
Additional information
Used simplifier rules: ⊦ ⌜m⌝ ≠ ∞; (s)