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Proof step 10 from proof tobuf-rev (previous step)

⌜n⌝ < # σ ⊦ # σ = ∞, ⌜σ.buf⌝ [n] = σ[n], n < # σ.buf

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
finp(σ) ⊦ # σ.buf = (# σ).n
Proof step 12:
⌜n⌝ < # σ, (# σ).n ≤ n ⊦ # σ = ∞, ⌜σ.buf⌝ [n] = σ[n]

Rule argument

Additional information

Used simplifier rules: tobuf-size: finp(σ) ⊦ # σ.buf = (# σ).n;% ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ ¬ finp(σ0) → # σ0 = ∞; (s)