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Proof step 6 from proof datasize-add-empty-h (previous step)

subarray(buf, n0, n + 1) = mkempbuf(n + 1), n0 + n < # buf, ∀ buf, n0. subarray(buf, n0, n) = mkempbuf(n) ∧ n0 + n ≤ # buf → datasize(buf, n0 + n) = datasize(buf, n0) ⊦ (buf[n0 + n] = empty ⊃ datasize(buf, n0 + n);(n0 + n) + 1) = datasize(buf, n0)

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Proof step 7:
buf[n0 + n] = empty, subarray(buf, n0, n + 1) = mkempbuf(n + 1), n0 + n < # buf, ∀ buf, n0. subarray(buf, n0, n) = mkempbuf(n) ∧ n0 + n ≤ # buf → datasize(buf, n0 + n) = datasize(buf, n0) ⊦ datasize(buf, n0 + n) = datasize(buf, n0)
Proof step 19:
subarray(buf, n0, n + 1) = mkempbuf(n + 1), n0 + n < # buf, ∀ buf, n0. subarray(buf, n0, n) = mkempbuf(n) ∧ n0 + n ≤ # buf → datasize(buf, n0 + n) = datasize(buf, n0) ⊦ (n0 + n) + 1 = datasize(buf, n0), buf[n0 + n] = empty

Rule argument

pos: right 1

Proof step 6 from proof datasize-add-empty-h (previous step)

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Rule argument

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