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Proof step 2 from proof datasize-append-empty-h (previous step)

m ≤ # buf0 + # buf1, m ≥ # buf0 → datasize(buf1, m - # buf0) = 0 ⊦ datasize(buf0 + buf1, m) = datasize(buf0, min(m, # buf0))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
m ≤ # buf0 + # buf1, # buf0 ≤ m → datasize(buf1, m - # buf0) = 0 ⊦ datasize(buf0 + buf1, m) = datasize(buf0, min(m, # buf0))

Rule argument

Additional information

Used simplifier rules: ⊦ n ≥ m ↔ m ≤ n; (s)