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Proof step 15 from proof datasize-append-h-new (previous step)

buf1[n] = empty, n < # buf1, ∀ buf1, buf0. n ≤ # buf1 → # buf1 = 0 ∨ datasize(buf1, n) = 0 ∨ datasize(buf0 + buf1, n + # buf0) = # buf0 + datasize(buf1, n) ∨ n = 0 ⊦ (buf1[n] = empty ⊃ datasize(buf1, n);n + 1) = 0, datasize(buf0 + buf1, n + # buf0) = # buf0 + (buf1[n] = empty ⊃ datasize(buf1, n);n + 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
buf1[n] = empty, n < # buf1, ∀ buf1, buf0. n ≤ # buf1 → # buf1 = 0 ∨ datasize(buf1, n) = 0 ∨ datasize(buf0 + buf1, n + # buf0) = # buf0 + datasize(buf1, n) ∨ n = 0 ⊦ datasize(buf0 + buf1, n + # buf0) = # buf0 + datasize(buf1, n), datasize(buf1, n) = 0

Proof step 15 from proof datasize-append-h-new (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information