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Proof step 7 from proof datasize-append-h-new (previous step)

m = n0 + # buf0, # buf0 < m, m ≤ # buf0 + # buf1, # buf0 ≤ m ⊦ # buf1 = 0, datasize(buf0 + buf1, m) = (datasize(buf1, n0) = 0 ⊃ datasize(buf0, # buf0);# buf0 + datasize(buf1, n0))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
n0 ≤ # buf1 ⊦ # buf1 = 0, datasize(buf0 + buf1, n0 + # buf0) = (datasize(buf1, n0) = 0 ⊃ datasize(buf0, # buf0);# buf0 + datasize(buf1, n0)), n0 = 0

Rule argument

Additional information

Used simplifier rules: ⊦ m < m + n ↔ n ≠ 0; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m + n ≤ m + n0 ↔ n ≤ n0; (s)% ⊦ m < n → m ≤ n; (s)