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Proof step 19 from proof datasize-empbuf-h (previous step)

n0 < n, ∀ buf0, n. n0 + # buf ≤ # buf0 + n → datasize(buf0 + mkempbuf(n), n0 + # buf) = datasize(buf0, min(# buf0, n0 + # buf)) ⊦ datasize(buf + mkempbuf(n), n0 + # buf) = datasize(buf, # buf)

User applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: buf, n abort: F discard: T computed: T

Additional information

Used simplifier rules: ⊦ m + n ≤ m + n0 ↔ n ≤ n0; (s)% ⊦ m < n → m ≤ n; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic% ⊦ min(n0 + m, m) = m; (s)%min-comm: ⊦ min(n0, n1) = min(n1, n0); from specification min-max Used terms: buf, n