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Proof step 11 from proof datasize-further (previous step)

0 = (buf[n] = empty ⊃ datasize(buf, n);n + 1), ∀ buf. 0 = datasize(buf, n) ↔ (∀ n0. n0 < n → buf[n0] = empty) ⊦ ∀ n0. ¬ n < n0 → buf[n0] = empty

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
0 = (buf[n] = empty ⊃ datasize(buf, n);n + 1), n0 ≤ n, ∀ buf. 0 = datasize(buf, n) ↔ (∀ n0. n0 < n → buf[n0] = empty) ⊦ buf[n0] = empty

Rule argument

Additional information

Used simplifier rules: ⊦ m < n ↔ ¬ n ≤ m; (ss)