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Proof step 13 from proof datasize-further (previous step)

0 = datasize(buf, n), buf[n] = empty, n0 ≤ n, ∀ buf. 0 = datasize(buf, n) ↔ (∀ n0. n0 < n → buf[n0] = empty) ⊦ buf[n0] = empty

Heuristic quantifier applied rule all left

And obtained the following new goals

Proof step 14:
0 = datasize(buf, n) ↔ (∀ n0. n0 < n → buf[n0] = empty), 0 = datasize(buf, n), buf[n] = empty, n0 ≤ n, ∀ buf. 0 = datasize(buf, n) ↔ (∀ n0. n0 < n → buf[n0] = empty) ⊦ buf[n0] = empty

Rule argument

pos: left 4 terms: buf

Additional information

Used terms: buf