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Proof step 15 from proof datasize-further (previous step)

0 = datasize(buf, n), buf[n] = empty, n0 ≤ n, ∀ buf. 0 = datasize(buf, n) ↔ (∀ n0. n0 < n → buf[n0] = empty), ∀ n0. n0 < n → buf[n0] = empty ⊦ buf[n0] = empty

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: n0

Additional information

Used simplifier rules: ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ m ≤ n → (n ≤ m ↔ m = n); (s) Used terms: n0