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Proof step 17 from proof datasize-further (previous step)

buf[n] = empty, ∀ n0. ¬ n < n0 → buf[n0] = empty, ∀ buf. 0 = datasize(buf, n) ↔ (∀ n0. n0 < n → buf[n0] = empty) ⊦ 0 = datasize(buf, n)

Heuristic quantifier applied rule all left

And obtained the following new goals

Proof step 18:
0 = datasize(buf, n) ↔ (∀ n0. n0 < n → buf[n0] = empty), buf[n] = empty, ∀ buf. 0 = datasize(buf, n) ↔ (∀ n0. n0 < n → buf[n0] = empty), ∀ n0. ¬ n < n0 → buf[n0] = empty ⊦ 0 = datasize(buf, n)

Rule argument

pos: left 3 terms: buf

Additional information

Used terms: buf