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Proof step 19 from proof datasize-further (previous step)

buf[n] = empty, n0 < n, ∀ buf. 0 = datasize(buf, n) ↔ (∀ n0. n0 < n → buf[n0] = empty), ∀ n0. ¬ n < n0 → buf[n0] = empty ⊦ 0 = datasize(buf, n), buf[n0] = empty

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 4 terms: n0

Additional information

Used simplifier rules: ⊦ m < n → ¬ n < m; (s) Used terms: n0