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Proof step 71 from proof datasize-further (previous step)

buf[n0] = empty, datasize(buf, n) = datasize(buf, n0), n < # buf, n ≤ n0, ∀ n1. n ≤ n1 ∧ ¬ n0 < n1 → buf[n1] = empty, ∀ n1. n < n1 ∧ ¬ n0 < n1 → buf[n1] = empty ⊦ n + 1 = datasize(buf, n0), buf[n] = empty, (n ≤ n2 ∧ n2 < n0 → buf[n2] = empty) ∧ n < n0 ∧ (n < n1 ∧ n1 < n0 → buf[n1] = empty)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: n

Additional information

Used simplifier rules: ⊦ m ≤ m; (s)% ⊦ m ≤ n → (n < m ↔ false); (s) Used terms: n