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Proof step 21 from proof datasize-le-h (previous step)

buf[m1] = empty, datasize(buf, m1) < # buf, n < # buf, m1 < # buf, datasize(buf, m1) < m, datasize(buf, m1) ≤ m1, m ≤ # buf, datasize(buf, m1) ≤ n, m ≤ n + 1, n ≤ m1, ∀ buf, m. m1 ≤ # buf → (m ≤ datasize(buf, m1) ↔ (∃ n. m ≤ n + 1 ∧ n < m1 ∧ buf[n] ≠ empty)) ∨ m = 0 ⊦ buf[n] = empty, ∃ n. m ≤ n + 1 ∧ n < m1 ∧ buf[n] ≠ empty

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: n

Additional information

Used simplifier rules: ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ m ≤ n → (n ≤ m ↔ m = n); (s) Used terms: n