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Proof step 6 from proof datasize-samebuf-h (previous step)

m < # buf, n0 < # buf, (buf[n0] = empty ⊃ datasize(buf, n0);n0 + 1) < datasize(buf, m), m ≤ n0, ∀ m0, buf0. ¬ m0 < n0 ∨ ¬ datasize(buf0, n0) < datasize(buf0, m0) ∨ ¬ m0 < # buf0 ∨ ¬ n0 ≤ # buf0 ⊦

User applied rule all left

And obtained the following new goals

Proof step 7:
(buf[n0] = empty ⊃ datasize(buf, n0);n0 + 1) < datasize(buf, m), n0 < # buf, m < # buf, m ≤ n0, ¬ m < n0 ∨ ¬ datasize(buf, n0) < datasize(buf, m) ∨ ¬ m < # buf ∨ ¬ n0 ≤ # buf ⊦

Rule argument

pos: left 5 terms: m, buf abort: F discard: T computed: T

Additional information

Used terms: m, buf