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Proof step 4 from proof datasize-subarray (previous step)

m0 + m1 = # buf ⊦ datasize(subarray(buf, m0, m1), m1) = (datasize(buf, m0 + m1) ≤ m0 ⊃ 0;datasize(buf, m0 + m1) - m0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ m0 + m1 = # buf ∧ m ≤ m1 → datasize(subarray(buf, m0, m1), m) = (datasize(buf, m0 + m) ≤ m0 ⊃ 0;datasize(buf, m0 + m) - m0)

Rule argument

spec: <toplevel> name: datasize-subarray-h seq: ⊦ m0 + m1 = # buf ∧ m ≤ m1 → datasize(subarray(buf, m0, m1), m) = (datasize(buf, m0 + m) ≤ m0 ⊃ 0;datasize(buf, m0 + m) - m0) subst: [m, m1, m0, buf] → [m1, m1, m0, buf] flags: <all paths>

Additional information

Used simplifier rules: ⊦ m ≤ m; (s) Used terms: m1, m1, m0, buf