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Proof step 2 from proof datasize-subarray0-h (previous step)

m ≤ # buf, m0 ≤ m ⊦ datasize(subarray(buf, 0, m), m0) = datasize(buf, m0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
m0 ≤ m, m ≤ # buf, m0 ≤ # buf ⊦ datasize(subarray(buf, 0, m), m0) = datasize(buf, m0)

Rule argument

Additional information

Used simplifier rules: let: ⊦ n ≤ n0 ∧ n0 ≤ n1 → n ≤ n1; (forward) from specification nat